Physics · Electrostatics

JEE Main 2024 — 8 April, Shift 1 — Question 43

Two charged conducting spheres of radii $a$ and $b$ are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

Option A:
$\sqrt{\mathrm{ab}}$
Option B:
ab
Option C:
$\frac{a}{b}$
Correct
Option D:
$\frac{b}{a}$

Answer: C

Step-by-step solution

Potential at surface will be same

$\frac{\mathrm{Kq}_{1}}{\mathrm{a}}=\frac{\mathrm{Kq}_{2}}{\mathrm{~b}}$

$\frac{\mathrm{q}_{1}}{\mathrm{q}_{2}}=\frac{\mathrm{a}}{\mathrm{b}}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 8 April, Shift 1
Subject: Physics
Chapter: Electrostatics
Topic: Properties of Conductors and Redistribution of Charge

An electric field, overrightarrow E=frac2 hat i+6 hat j+8 hat k√(6) passes through the surface of 4 m^2 area having unit vector hatn=…

Answer: C

Step-by-step solution

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