Physics · Current Electricity

JEE Main 2025 — 3 April, Evening Shift — Question 61

A motor operating on 100 V draws a current of 1 A . If the efficiency of the motor is $91.6 \%$ , then the loss of power in units of cal/s is

Answer: D

$P_{0}=100 \times 1=100 \mathrm{~W}$

Loss $=(1-\eta) p_{0}=\frac{8.4}{100} \times 100=8.4 \mathrm{~J}$

Loss $=\frac{8.4}{4.2} \mathrm{cal}=2$

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