A particle moves along the x -axis and has its displacement x varying with time t according to the equation: x=c 0 (t 2 -2 )+c(t-2) 2 Where co and cone constants of appropriate dimensions. Then, which of the following statements is correct?

The acceleration of the particle is 2 (c+c 0 )

The acceleration of the particle is 2 c 0

The initial velocity of the particle is 4 c

The acceleration of the particle is 2 c

Physics · Motion in one Dimension

JEE Main 2025 — 3 April, Evening Shift — Question 60

A particle moves along the $x$ -axis and has its displacement $x$ varying with time $t$ according

to the equation: $x=c_{0}\left(t^{2}-2\right)+c(t-2)^{2}$ Where co and cone constants

of appropriate dimensions.

Then, which of the following statements is correct?

$x=C_{0}\left(t^{2}-2\right)+C\left(t^{2}+4-2 t\right)$

$V=C_{0}(2 t)+C(2 t-2)$ at $t=0$

$v=-2 C$ $a=2 C_{0}+2 C$

Answer key and solution verified before publishing.

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