Physics · Work, Power & Energy

JEE Main 2025 — 3 April, Evening Shift — Question 62

Two cylindrical vessels of equal cross sectional area of $2 \mathrm{~m}^{2}$ contain water upto heights 10 m and 6 m , respectively If the vessels are connected at their bottom then the work done by the force of gravity is (Density of water is $10^{3} \mathrm{~kg} / \mathrm{m}^{3}$ and $g=10 \mathrm{~m} / \mathrm{s}^{2}$ )

Option A:
$4 \times 10^{4} \mathrm{~J}$
Option B:
$8 \times 10^{4} \mathrm{~J}$
Correct
Option C:
$6 \times 10^{4} \mathrm{~J}$
Option D:
$1 \times 10^{5} \mathrm{~J}$

Answer: B

Step-by-step solution

Effectively shaded portion has descended

$|w|=\Delta m g \Delta h$

$=(\rho 2 A) g \times 2$

$=10^{3} \times 2 \times 40$ $=8 \times 10^{4} \mathrm{~J}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 3 April, Evening Shift
Subject: Physics
Chapter: Work, Power & Energy
Topic: Applications of Conservation of Mechanical Energy

A block of mass 1 kg , moving along x with speed v i=10 m / s enters a rough region ranging from x=0.1 m to x=1.9 m . The retarding force…

Answer: B

Step-by-step solution

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