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Physics · Newton's Laws of Motion

JEE Main 2024 — 1 February, Shift 2 — Question 39

A cricket player catches a ball of mass 120 g moving with 25 m/s25 \mathrm{~m} / \mathrm{s} speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):

  1. Option A:

    24

  2. Option B:

    12

  3. Option C:

    25

  4. Option D:

    30

    Correct

Answer: D

Step-by-step solution

Fav=ΔpΔt\quad \mathrm{F}_{\mathrm{av}}=\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}} =0.12×250.1=30 N=\frac{0.12 \times 25}{0.1}=30 \mathrm{~N}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Physics
Chapter
Newton's Laws of Motion
Topic
Application of NLM and Impulse

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