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Physics · Electromagnetic Waves

JEE Main 2024 — 1 February, Shift 2 — Question 38

If frequency of electromagnetic wave is 60 MHz and it travels in air along z direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in m ) is :

  1. Option A:

    2.5

  2. Option B:

    10

  3. Option C:

    5

    Correct
  4. Option D:

    2

Answer: C

Step-by-step solution

λ=cf=3×10860×106=5 m\lambda=\frac{\mathrm{c}}{\mathrm{f}}=\frac{3 \times 10^{8}}{60 \times 10^{6}}=5 \mathrm{~m}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Displacement Current and Equation of EM Waves
If frequency of electromagnetic wave is 60 MHz and it travels in air… | JEE Main 2024 PYQ with Solution · DhiX AI