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Physics · Atomic Physics

JEE Main 2024 — 1 February, Shift 2 — Question 40

Monochromatic light of frequency 6×1014 Hz6 \times 10^{14} \mathrm{~Hz} is produced by a laser. The power emitted is 2×10−3 W2 \times 10^{-3} \mathrm{~W}. How many photons per second on an average, are emitted by the source? (Given h=6.63×10−34Js\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js} )

  1. Option A:

    9×10189 \times 10^{18}

  2. Option B:

    6×10156 \times 10^{15}

  3. Option C:

    5×10155 \times 10^{15}

    Correct
  4. Option D:

    7×10167 \times 10^{16}

Answer: C

Step-by-step solution

P=nhv\mathrm{P}=\mathrm{nh} v

n=Phν=2×10−36.63×10−34×6×1014\mathrm{n}=\frac{\mathrm{P}}{\mathrm{h} \nu}=\frac{2 \times 10^{-3}}{6.63 \times 10^{-34} \times 6 \times 10^{14}}

=5×1015=5 \times 10^{15}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Physics
Chapter
Atomic Physics
Topic
Photon Theory of Light and Radiation Pressure

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