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Physics · Newton's Laws of Motion

JEE Main 2024 — 1 February, Shift 2 — Question 50

A body of mass 4 kg experiences two forces F→1=5i^+8j^+7k^\overrightarrow{\mathrm{F}}_{1}=5 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}+7 \hat{\mathrm{k}} and F→2=3i^−4j^−3k^\overrightarrow{\mathrm{F}}_{2}=3 \hat{\mathrm{i}}-4 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}. The acceleration acting on the body is :

  1. Option A:

    −2i^−j^−k^-2 \hat{i}-\hat{j}-\hat{k}

  2. Option B:

    4i^+2j^+2k^4 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}

  3. Option C:

    2i^+j^+k^2 \hat{i}+\hat{j}+\hat{k}

    Correct
  4. Option D:

    2i^+3j^+3k^2 \hat{i}+3 \hat{j}+3 \hat{k}

Answer: C

Step-by-step solution

Net force =8i^+4j^+4k^=8 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}+4 \hat{\mathrm{k}} a→=F→m=2i^+j^+k^\overrightarrow{\mathrm{a}}=\frac{\overrightarrow{\mathrm{F}}}{\mathrm{m}}=2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Physics
Chapter
Newton's Laws of Motion
Topic
Application of NLM and Impulse

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