Physics · Mechanical Properties of Matter

JEE Main 2024 — 1 February, Shift 2 — Question 37

A big drop is formed by coalescing 1000 small droplets of water. The surface energy will become :

  1. Option A:

    100 times

  2. Option B:

    10 times

  3. Option C:

    1100\frac{1}{100} th

  4. Option D:

    110\frac{1}{10} th

    Correct

Answer: D

Step-by-step solution

Lets say radius of small droplets is rr and that of big drop is RR

43πR3=100043πr3\frac{4}{3} \pi \mathrm{R}^{3}=1000 \frac{4}{3} \pi \mathrm{r}^{3}

R=10r\mathrm{R}=10 \mathrm{r}

Ui=1000(4πr2 S)\mathrm{U}_{\mathrm{i}}=1000\left(4 \pi \mathrm{r}^{2} \mathrm{~S}\right)

Uf=4πR2 S\mathrm{U}_{\mathrm{f}}=4 \pi \mathrm{R}^{2} \mathrm{~S} =100(4πr2S)=100\left(4 \pi r^{2} S\right)

Uf=110Ui\mathrm{U}_{\mathrm{f}}=\frac{1}{10} \mathrm{U}_{\mathrm{i}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Surface Tension and Surface Energy
A big drop is formed by coalescing 1000 small droplets of water. The… | JEE Main 2024 PYQ with Solution · DhiX AI