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Physics · Semiconductor and Electronic Devices

JEE Main 2024 — 1 February, Shift 2 — Question 36

Conductivity of a photodiode starts changing only if the wavelength of incident light is less than 660 nm . The band gap of photodiode is found to be (X8)eV\left(\frac{\mathrm{X}}{8}\right) \mathrm{eV}. The value of X is : (Given, h=6.6×10−34Js\mathrm{h}=6.6 \times 10^{-34} \mathrm{Js}, e=1.6×10−19C\mathrm{e}=1.6 \times 10^{-19} \mathrm{C} )

  1. Option A:

    15

    Correct
  2. Option B:

    11

  3. Option C:

    13

  4. Option D:

    21

Answer: A

Step-by-step solution

Eg=hcλ=6.6×10−34×3×108660×10−9 J\mathrm{E}_{\mathrm{g}}=\frac{\mathrm{hc}}{\lambda}=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{660 \times 10^{-9}} \mathrm{~J}

=6.6×10−34×3×108660×10−9×1.6×10−19eV=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{660 \times 10^{-9} \times 1.6 \times 10^{-19}} \mathrm{eV}

=158eV=\frac{15}{8} \mathrm{eV} So x=15\mathrm{x}=15

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
1 February, Shift 2
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
p-n Diode and its Applications
Conductivity of a photodiode starts changing only if the wavelength… | JEE Main 2024 PYQ with Solution · DhiX AI