Physics · Mechanical Properties of Matter

JEE Main 2024 — 1 February, Shift 2 — Question 54

One end of a metal wire is fixed to a ceiling and a load of 2 kg hangs from the other end. A similar wire is attached to the bottom of the load and another load of 1 kg hangs from this lower wire. Then the ratio of longitudinal strain of upper wire to that of the lower wire will be ________\_\_\_\_\_\_\_\_ . [Area of cross section of wire =0.005 cm2=0.005 \mathrm{~cm}^{2}, Y=2×1011Nm−2\mathrm{Y}=2 \times 10^{11} \mathrm{Nm}^{-2} and g=10 ms−2]\left.\mathrm{g}=10 \mathrm{~ms}^{-2}\right]

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

ΔL=FLAY\Delta \mathrm{L}=\frac{\mathrm{FL}}{\mathrm{AY}} ΔLL=FAY\frac{\Delta \mathrm{L}}{\mathrm{L}}=\frac{\mathrm{F}}{\mathrm{AY}} ΔL1 L1Δ L2 L2=F1 F2=3010=3\frac{\frac{\Delta \mathrm{L}_{1}}{\mathrm{~L}_{1}}}{\frac{\Delta \mathrm{~L}_{2}}{\mathrm{~L}_{2}}}=\frac{\mathrm{F}_{1}}{\mathrm{~F}_{2}}=\frac{30}{10}=3

Answer key and solution verified before publishing.

Practise Mechanical Properties of Matter

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2024
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Stress,Strain and Modulus of Elasticity
One end of a metal wire is fixed to a ceiling and a load of 2 kg… | JEE Main 2024 PYQ with Solution · DhiX AI