Chemistry · Coordination Compounds

JEE Main 2026 — 2 April, Morning Shift — Question 57

5.33 g of CrCl3⋅6H2O\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}, which is a 1:31: 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with AgNO3\mathrm{AgNO}_{3}, results in 8.61 g of AgCl . The ratio of moles of complex reacted and moles of AgCl formed is ____\_\_\_\_ ×10−2\times 10^{-2}. (Nearest integer) [Molar mass in gmol−1Cr:52,Ag:108,Cl:35.5\mathrm{g} \mathrm{mol}^{-1} \mathrm{Cr}: 52, \mathrm{Ag}: 108, \mathrm{Cl}: 35.5, H:1,O:16]\mathrm{H}: 1, \mathrm{O}: 16]

Answer: 33

Numerical answer — enter this value.

Step-by-step solution

[Cr(H2O)6]Cl3+AgNO3 excess →3AgCl(s) ppt  no. of moles of complex reacted  no. of moles of AgCl precipitated ×100=13×100=33.3\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{3}+\underset{\text { excess }}{\mathrm{AgNO}_{3}} \rightarrow \underset{\text { ppt }}{3 \mathrm{AgCl}(\mathrm{s})} \frac{\text { no. of moles of complex reacted }}{\text { no. of moles of } \mathrm{AgCl} \text { precipitated }} \times 100 =\frac{1}{3} \times 100=33.3

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Fundamentals of Co-ordination Compounds
5.33 g of CrCl 3 × 6 H 2 O , which is a 1: 3 electrolyte, is… | JEE Main 2026 PYQ with Solution · DhiX AI