Match List - I with List - II. List – I Chromium (III) Complexes (en = ethylene diamine) List – II Δ 0 ( c m - 1 ) --- --- A. [ Cr ( CN ) 6 ] 3- I. 15,060 B. [ CrF 6 ] 3- II. 17,400 C. . [ Cr ( H 2 O ) 6 ) ] 3+ III. 22,300 D. [ Cr ( en ) 3 ] 3+ IV. 26,600 Choose the correct answer from the options given below:

Chemistry · Coordination Compounds

JEE Main 2026 — 2 April, Morning Shift — Question 50

Match List - I with List - II.

List – I Chromium (III) Complexes (en = ethylene diamine)	List – II $\Delta_{\mathbf{0}}\left(\mathbf{c m}^{-\mathbf{1}}\right)$
A. $\quad\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}$	I. 15,060
B. $\quad\left[\mathrm{CrF}_{6}\right]^{3-}$	II. 17,400
C. $\left.\quad\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right)\right]^{3+}$	III. 22,300
D. $\quad\left[\mathrm{Cr}(\mathrm{en})_{3}\right]^{3+}$	IV. 26,600

Choose the correct answer from the options given below:

Option A:
A-I, B-II, C-III, D-IV
Option B:
A-II, B-III, C-IV, D-I
Option C:
A-III, B-IV, C-I, D-II
Option D:
A-IV, B-I, C-II, D-III
Correct

Answer: D

Step-by-step solution

Sol. CFSE is proportional to strength of ligand followed by chelation. $\mathrm{CN}^{-}$ is stronger ligand than en $\mathrm{CN}^{-}>\mathrm{en}>\mathrm{H}_{2} \mathrm{O}>\mathrm{F}^{-}$

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Fundamentals of Co-ordination Compounds

5.33 g of CrCl 3 × 6 H 2 O , which is a 1: 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions…

Answer: D

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