The plot of osmotic pressure ( Pi ) vs concentration ( mol L -1 ) for a solution gives a straight line with slope 25.73 L bar mol -1 . The temperature at which the osmotic pressure measurement is done is (Use R =0.083 L bar mol -1 K -1 )

Chemistry · Solutions and Colligative Properties

NEET (UG) 2024 — Question 90

The plot of osmotic pressure ( $\Pi$ ) vs concentration ( $\mathrm{mol} \mathrm{L}^{-1}$ ) for a solution gives a straight line with slope $25.73 \mathrm{~L} \mathrm{bar} \mathrm{mol}^{-1}$ . The temperature at which the osmotic pressure measurement is done is (Use R $=0.083 \mathrm{~L}$ bar $\mathrm{mol}^{-1} \mathrm{~K}^{-1}$ )

Option A:
$37^{\circ} \mathrm{C}$
Correct
Option B:
$310^{\circ} \mathrm{C}$
Option C:
$25.73^{\circ} \mathrm{C}$
Option D:
$12.05^{\circ} \mathrm{C}$

Answer: A

Step-by-step solution

$\Pi=$ CRT

Slope $=$ RT

$25.73=0.083 \times T$

$\mathrm{T}=\frac{25.73}{0.083}=309.47 \approx 310 \mathrm{~K}$

$\therefore$ Temperature in ${ }^{\circ} \mathrm{C}=310-273$

=37^{\circ} \mathrm{C}

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Exam: NEET (UG) 2024
Paper: 2024 paper
Subject: Chemistry
Chapter: Solutions and Colligative Properties
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