Start free

Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

NEET (UG) 2024 — Question 91

Given below are certain cations. Using inorganic qualitative analysis, arrange them in increasing group number from 0 to VI .

A. Al3+\mathrm{Al}^{3+}

B. Cu2+\mathrm{Cu}^{2+}

C. Ba2+\mathrm{Ba}^{2+}

D. Co2+\mathrm{Co}^{2+}

E. Mg2+\mathrm{Mg}^{2+}

Choose the correct answer from the options given below.

  1. Option A:

    B,A,D,C,EB, A, D, C, E

    Correct
  2. Option B:

    B,C,A,D,EB, C, A, D, E

  3. Option C:

    E,C,D,B,AE, C, D, B, A

  4. Option D:

    E,A,B,C,DE, A, B, C, D

Answer: A

Step-by-step solution

GroupCations
Group-IICu2+\text{C}{{\text{u}}^{2+}}
Group-IIIAl3+\text{A}{{\text{l}}^{3+}}
Group-IVCo2+\text{C}{{\text{o}}^{2+}}
Group-VBa2+\text{B}{{\text{a}}^{2+}}
Group-VIMg2+\text{M}{{\text{g}}^{2+}}

The correct order of group number of ions is

Cu(B)2+<Al3+(A)<Co2+(D)<Ba2+ (C) <Mg2+(E)\mathrm{Cu}_{(\mathrm{B})}^{2+}<\underset{(\mathrm{A})}{\mathrm{Al}^{3+}}<\underset{(\mathrm{D})}{\mathrm{Co}^{2+}}<\underset{\text { (C) }}{\mathrm{Ba}^{2+}}<\underset{(\mathrm{E})}{\mathrm{Mg}^{2+}}

∴\therefore The correct order is B, A, D, C, E

Answer key and solution verified before publishing.

Practise Practical Inorganic chemistry (Qualitative Analysis)

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
NEET (UG) 2024
Paper
2024 paper
Subject
Chemistry
Chapter
Practical Inorganic chemistry (Qualitative Analysis)
Topic
Identifical of Cations (Group 4 to 6 and Zero)

More Practical Inorganic chemistry (Qualitative Analysis) questions from this paper

Given below are certain cations. Using inorganic qualitative… | NEET (UG) 2024 PYQ with Solution · DhiX AI