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Physics · Atomic Physics

NEET (UG) 2024 — Question 10

The graph which shows the variation of (1λ2)\left(\frac{1}{\lambda^{2}}\right) and its kinetic energy, EE is (where λ\lambda is de Broglie wavelength of a free particle):

  1. Option A:
    Option A figure
  2. Option B:
    Option B figure
  3. Option C:
    Option C figure
  4. Option D:
    Option D figure
    Correct

Answer: D

Step-by-step solution

de-Broglie wavelength λ=hP=hmv=h2mE\lambda=\frac{h}{P}=\frac{h}{m v}=\frac{h}{\sqrt{2 m E}} where E=12mv2E=\frac{1}{2} m v^{2}

Squaring both sides, λ2=h24m2E\lambda^{2}=\frac{h^{2}}{4 m^{2} E}

⇒1λ2=( constant ) \Rightarrow \frac{1}{\lambda^{2}}=(\text { constant })

Graph passes through origin with constant slope.

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Paper
2024 paper
Subject
Physics
Chapter
Atomic Physics
Topic
Dual Nature of Matter

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