Physics · Atomic Physics

NEET (UG) 2024 — Question 27

Match List I with List II.

List I (Spectral Lines of Hydrogen for transitions from)List II(Wavelengths (nm))
A.n2=3{{n}_{2}}=3 to n1=2{{n}_{1}}=2I.410.2
B.n2=4{{n}_{2}}=4 to n1=2{{n}_{1}}=2II.434.1
C.n2=5{{n}_{2}}=5 to n1=2{{n}_{1}}=2III.656.3
D.n2=6{{n}_{2}}=6 to n1=2{{n}_{1}}=2IV.486.1

Choose the correct answer from the options given below:

  1. Option A:

    A-II, B-I, C-IV, D-III

  2. Option B:

    A-III, B-IV, C-II, D-I

    Correct
  3. Option C:

    A-IV, B-III, C-I, D-II

  4. Option D:

    A-I, B-II, C-III, D-IV

Answer: B

Step-by-step solution

Energy difference ΔE=hcλ\Delta E=\frac{h c}{\lambda}

∴λ∝1ΔE\therefore \lambda \propto \frac{1}{\Delta E}

(ΔE)6−2>(ΔE)5−2>(ΔE)4−2>(ΔE)3−2(\Delta E)_{6-2}>(\Delta E)_{5-2}>(\Delta E)_{4-2}>(\Delta E)_{3-2}

λ6−2<λ5−2<λ4−2<λ3−2\lambda_{6-2}<\lambda_{5-2}<\lambda_{4-2}<\lambda_{3-2}

 A-III, B-IV, C-II, D-I  \text { A-III, B-IV, C-II, D-I }

Answer key and solution verified before publishing.

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Exam
NEET (UG) 2024
Subject
Physics
Chapter
Atomic Physics
Topic
Hydrogen Spectrum
Match List I with List II. List I (Spectral Lines of Hydrogen for… | NEET (UG) 2024 PYQ with Solution · DhiX AI