X g of nitrobenzene on nitration gave 4.2 g of m -dinitrobenzene. X = \ \ \ \ \ g. (nearest integer) [Given: molar mass (in g mol -1 ) C: 12, H: 1, O: 16, N: 14]

Chemistry · Aromatic Compounds

JEE Main 2025 — 3 April, Evening Shift — Question 16

X g of nitrobenzene on nitration gave 4.2 g of m -dinitrobenzene. $\mathrm{X}=$ $\_\_\_\_\_$ g. (nearest integer) [Given: molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$ ) C: 12, H: 1, O: 16, N: 14]

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

$\frac{x}{123}=\frac{4.2}{168}$

$X=3.075 \mathrm{~g}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 3 April, Evening Shift
Subject: Chemistry
Chapter: Aromatic Compounds
Topic: Preparation of Arenes