Start free

Chemistry · Structure of Atom

JEE Main 2025 — 3 April, Evening Shift — Question 15

For electrons in ' 2s2s ' and ' 2p2p ' orbitals, the orbital angular momentum values, respectively, are

  1. Option A:

    0 and 2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi}

    Correct
  2. Option B:

    0 and 6 h2π\sqrt{6} \frac{\mathrm{~h}}{2 \pi}

  3. Option C:

    2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi} and 0

  4. Option D:

    h2π\frac{\mathrm{h}}{2 \pi} and 2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi}

Answer: A

Step-by-step solution

The orbital angular momentum is given by L=l(l+1) h2πL = \sqrt{l(l+1)}\,\frac{h}{2\pi}

For the 2s2s orbital: l=0l = 0

L=0(0+1) h2π=0L = \sqrt{0(0+1)}\,\frac{h}{2\pi} = 0

For the 2p2p orbital: l=1l = 1

L=1(1+1) h2π=2 h2πL = \sqrt{1(1+1)}\,\frac{h}{2\pi} = \sqrt{2}\,\frac{h}{2\pi}

Answer key and solution verified before publishing.

Practise Structure of Atom

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2025
Paper
3 April, Evening Shift
Subject
Chemistry
Chapter
Structure of Atom
Topic
Mathematical & Graphical Aspects of Quantum Mechanical Model
For electrons in ' 2s ' and ' 2p ' orbitals, the orbital angular… | JEE Main 2025 PYQ with Solution · DhiX AI