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Physics · Atomic Physics

JEE Main 2026 — 2 April, Morning Shift — Question 42

What is the energy (in J atom −1{ }^{-1} ) required for the following process? Li2+(g)→Li3+(g)+e−\mathrm{Li}^{2+}(\mathrm{g}) \rightarrow \mathrm{Li}^{3+}(\mathrm{g})+\mathrm{e}^{-} (Take the ionization energy for the H atom in the ground state as 2.18×10−18 J−12.18 \times 10^{-18} \mathrm{~J}^{-1} atom −1{ }^{-1} )

  1. Option A:

    8.72×10−188.72 \times 10^{-18}

  2. Option B:

    1.962×10−181.962 \times 10^{-18}

  3. Option C:

    1.962×10−171.962 \times 10^{-17}

    Correct
  4. Option D:

    6.54×10−176.54 \times 10^{-17}

Answer: C

Step-by-step solution

ELi2+=EH×z2E_{L i^{2+}}=E_{H} \times z^{2}

=2.18×10−18×2=1.962×10−17 Jatom−1\begin{aligned} & =2.18 \times 10^{-18} \times^{2} & =1.962 \times 10^{-17} \mathrm{~J} \mathrm{atom}^{-1} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
2 April, Morning Shift
Subject
Physics
Chapter
Atomic Physics
Topic
Rutherford's and Bohr's Model of Atom

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