Physics · Atomic Physics

JEE Main 2026 — 2 April, Morning Shift — Question 14

Angular momentum of an electron in a hydrogen atom is $\frac{3h}{\pi}$ , then the energy of the electron is $\mathrm{eV}$ .

Option A:
$-1.51$
Option B:
$-0.85$
Option C:
$-0.38$
Correct
Option D:
$-0.28$

Answer: C

Step-by-step solution

$L = \frac{nh}{2\pi} = \frac{3h}{\pi} \Rightarrow n=6$ , $E = -\frac{13.6}{n^2} = -0.38\mathrm{eV}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 2 April, Morning Shift
Subject: Physics
Chapter: Atomic Physics
Topic: Rutherford's and Bohr's Model of Atom

Angular momentum of an electron in a hydrogen atom is 3h/π , then the… | JEE Main 2026 PYQ with Solution · DhiX AI