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Chemistry · Practical Organic Chemistry

JEE Main 2025 — 23 January, Morning Shift — Question 39

What amount of bromine will be required to convert 2 g of phenol into 2,4,62,4,6-tribromophenol ? (Given molar mass in gmol−1\mathrm{g} \mathrm{mol}^{-1} of C,H,O,Br\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{Br} are 12,1,16,8012,1,16,80 respectively)

  1. Option A:

    10.22 g

    Correct
  2. Option B:

    6.0 g

  3. Option C:

    4.0 g

  4. Option D:

    20.44 g

Answer: A

Step-by-step solution

figure

Moles of phenol =294=0.021=\frac{2}{94}=0.021

∴\therefore Moles of bromine =0.021×3=0.064=0.021 \times 3=0.064

∴\therefore Mass of bromine =0.064×160=10.22 g=0.064 \times 160=10.22 \mathrm{~g}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
23 January, Morning Shift
Subject
Chemistry
Chapter
Practical Organic Chemistry
Topic
Quantitative organic analysis

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