Chemistry · Practical Organic Chemistry

JEE Main 2025 — 23 January, Morning Shift — Question 46

During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is___ $\%$ .

(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{Ba}: 137, \mathrm{~S}: 32$ , O:16)

Answer: 40

Numerical answer — enter this value.

Millimoles of $\mathrm{BaSO}_{4}=\frac{466}{233}=2 \mathrm{~m} \mathrm{~mol}$

$\% \mathrm{~S}=\frac{\frac{466}{233} \times 32}{160} \times 100=40 \%$

Answer key and solution verified before publishing.

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