Wavenumber for a radiation having 5800\ AA wavelength is x × 10 4 \ cm -1 . The value of x is:

Chemistry · Structure of Atom

JEE Main 2024 — 8 April, Shift 2 — Question 85

Wavenumber for a radiation having $5800\ \mathrm{\AA}$ wavelength is $x \times 10^{4}\ \mathrm{cm^{-1}}$ . The value of $x$ is:

Numerical answer — enter this value.

Wavenumber, $\mathrm{\bar{\nu} = \frac{1}{\lambda}}$

Converting to wavelength, we have

\mathrm{5800\ \AA = 5800 \times 10^{-8}\ cm = 5.8 \times 10^{-5}\ cm}

\mathrm{\bar{\nu} = \frac{1}{5.8 \times 10^{-5}}}

\mathrm{\bar{\nu} = 1.724 \times 10^{4}\ cm^{-1}}

\mathrm{x = 1.724}

Answer key and solution verified before publishing.

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