Total number of unpaired electrons in the complex ion [ Co ( NH 3 ) 6 ] 3+ and [ NiCl 4 ] 2- is

Chemistry · Coordination Compounds

JEE Main 2024 — 8 April, Shift 2 — Question 84

Total number of unpaired electrons in the complex ion $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ and $\left[\mathrm{NiCl}_{4}\right]^{2-}$ is

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{Co}^{+3}: 3 \mathrm{~d}^{6} \quad \mathrm{t}_{2 \mathrm{~g}}^{2,2,2} \mathrm{e}_{\mathrm{g}}^{0,0}$

Unpaired $\mathrm{e}^{-}=0$

$\mathrm{Ni}^{+2}: 3 \mathrm{~d}^{8} \quad \mathrm{e}^{2,2} \mathrm{t}_{2}^{2,1,1}$

Unpaired $\mathrm{e}^{-}=2$

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Exam: JEE Main 2024
Paper: 8 April, Shift 2
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Theories of Bonding in Coordination Compounds

Match List-I with List-II. List 1 List 2 --- --- (A) [ Cr ( N H 3 ) 6 ]^3+ (I) 4.90 (B) [ NiC l 4 ]^2- (II) 3.87 (C) [ Co F 6 ]^3- (III)…

Answer: 2

Step-by-step solution

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