Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2024 — 8 April, Shift 2 — Question 86

A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ____\_\_\_\_ (Integer answer).

[Given: Molar mass in g mol−1\mathrm{g\ mol^{-1}} — Ethyl alcohol: 46, Water: 18]

Answer: 22

Numerical answer — enter this value.

Step-by-step solution

Mass of ethyl alcohol =1×46=46 g= \mathrm{1 \times 46 = 46\ g}

Mass of water =9×18=162 g= \mathrm{9 \times 18 = 162\ g}

Total mass of solution =208 g=\mathrm{208\ g}

Mass percent of solute (alcohol) = Mass   of   ethyl   alcohol  Total   mass   of   solution ×100=\frac{\text { Mass\; of \;ethyl \;alcohol }}{\text { Total \;mass\; of\; solution }} \times 100

Mass percent of solute =46208×100=22.1%= \mathrm{\frac{46}{208} \times 100 = 22.1\%}

Thus, the integer answer is 2222.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Percentage composition & Empirical Formula
A solution is prepared by adding 1 mole ethyl alcohol in 9 mole… | JEE Main 2024 PYQ with Solution · DhiX AI