Physics · Transverse waves

JEE Main 2025 — 8 April, Evening Shift — Question 57

Two strings with circular cross section and made of same material are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section $R$ is $v_{1}$ , and that in the other string having radius of cross section $R / 2$ is $v_{2}$ . Then $\frac{v_{2}}{v_{1}}=$

Option A:
8
Option B:
2
Correct
Option C:
$\sqrt{2}$
Option D:
4

Answer: B

Step-by-step solution

$v=\sqrt{\frac{T}{\mu}}$ and $\mu=\rho \pi R^{2}$

$\implies \frac{v_{1}}{v_{2}}=\sqrt{\frac{R_{2}^{2}}{R_{1}^{2}}}=\frac{R_{2}}{R_{1}}=\frac{1}{2}$

$\implies \frac{v_{2}}{v_{1}}=2$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 8 April, Evening Shift
Subject: Physics
Chapter: Transverse waves
Topic: Speed of Transverse waves

The amplitude and phase of a wave that is formed by the superposition of two harmonic travelling waves, y 1 (x, t)=4 sin (k x-omega t) and…

Answer: B

Step-by-step solution

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