Physics · Thermodynamics

JEE Main 2025 — 8 April, Evening Shift — Question 56

A monoatomic gas having $\gamma=\frac{5}{3}$ is stored in a thermally insulated container and the gas is suddenly compressed to $\left(\frac{1}{8}\right)^{\text {th }}$ of its initial volume. The ratio of final pressure and initial pressure is ( $\gamma$ is the ratio of specific heats of the gas at constant pressure and at constant volume)

Option A:
40
Option B:
28
Option C:
32
Correct
Option D:
16

Answer: C

Step-by-step solution

$P_{1} v_{1}^{\gamma}=P_{2} v_{2}^{\gamma}$

v_{2}=\frac{v_{1}}{8}

$\frac{P_{2}}{P_{1}}=\left(\frac{v_{1}}{v_{2}}\right)^{\gamma}=(8)^{\frac{5}{3}}=32$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 8 April, Evening Shift
Subject: Physics
Chapter: Thermodynamics
Topic: Different Thermodynamic Processes