Two p-block elements X and Y form fluroides of the type EF 3 . The fluoride compound XF 3 is a Lewis acid and YF 3 is a Lewis base. The hybridization of the central atoms of XF 3 and YF 3 respectively are

Chemistry · Chemical Bonding

JEE Main 2026 — 22 January, Morning Shift — Question 63

Two p-block elements X and Y form fluroides of the type $\mathrm{EF}_{3}$ . The fluoride compound $\mathrm{XF}_{3}$ is a Lewis acid and $\mathrm{YF}_{3}$ is a Lewis base. The hybridization of the central atoms of $\mathrm{XF}_{3}$ and $\mathrm{YF}_{3}$ respectively are

Option A:
Both $\mathrm{sp}^{3}$
Option B:
$s p^{2}$ and $s p^{3}$
Correct
Option C:
$s p^{3}$ and $s p^{2}$
Option D:
Both $\mathrm{sp}^{2}$

Answer: B

Step-by-step solution

$\mathrm{XF}_{3}=\mathrm{BF}_{3} ; \mathrm{sp}^{2}$ $\mathrm{YF}_{3}=\mathrm{NF}_{3} ; \mathrm{sp}^{3}$

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Exam: JEE Main 2026
Paper: 22 January, Morning Shift
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Valence Bond Theory (VBT)

The formal changes on the atoms marked as (1) to (4) in the Lewis representation of HnO 3 molecule respectively are

Answer: B

Step-by-step solution

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