Chemistry · Chemical Bonding

JEE Main 2026 — 22 January, Morning Shift — Question 50

The formal changes on the atoms marked as (1) to (4) in the Lewis representation of $\mathrm{HnO}_{3}$ molecule respectively are

Option A:
$+1,0,0,-1$
Option B:
$0,-1,0,+1$
Option C:
$0,+1,0,-1$
Correct
Option D:
$0,0,-1,+1$

Answer: C

Step-by-step solution

Consider the structure of $\mathrm{HNO}_{3}$ 1 :- 0 2 :- (+1) 3 :- 0 4 :- (-1) Formal charge $=$ valence e's - non bonding e's

-\left(\frac{\text { bonding electrons }}{2}\right)

Solution figure

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 22 January, Morning Shift
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Valence Bond Theory (VBT)

Two p-block elements X and Y form fluroides of the type EF 3 . The fluoride compound XF 3 is a Lewis acid and YF 3 is a Lewis base. The…

The formal changes on the atoms marked as (1) to (4) in the Lewis… | JEE Main 2026 PYQ with Solution · DhiX AI