Mathematics · Probability

JEE Main 2025 — 2 April, Morning Shift — Question 45

Three distinct numbers are selected randomly from the set {1,2,3,…,40}\{1,2,3, \ldots, 40\}. If the probability, that the selected members are in an increasing G.P., is mn,gcd⁡(m,n)=1\frac{m}{n}, \operatorname{gcd}(m, n)=1, then m+nm+n is equal to ____\_\_\_\_

Answer: 4949

Numerical answer — enter this value.

Step-by-step solution

Common ratioLast tripletTotal
r=210, 20, 4010
r=34, 12, 364
r=42, 8, 322
r=51, 5, 251
r=61, 6, 361
Total=18

Total choices =40C3=9880={ }^{40} C_{3}=9880

Required probability =189880=94940=mn=\frac{18}{9880}=\frac{9}{4940}=\frac{m}{n}

m+n=4949m+n=4949

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Probability
Topic
Problems based on P & C
Three distinct numbers are selected randomly from the set \ 1,2,3… | JEE Main 2025 PYQ with Solution · DhiX AI