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Physics · Electrostatics

JEE Main 2026 — 24 January, Morning Shift — Question 25

Three charges +2q.+3q+2 \mathrm{q} .+3 \mathrm{q} and -4 q are situated at (0,−3a),(2a,0)(0,-3 \mathrm{a}),(2 \mathrm{a}, 0) and (−2a,0)(-2 \mathrm{a}, 0) respectively in the xy plane. The resultant dipole moment about origin is ____\_\_\_\_

  1. Option A:

    2qa(3j^−i^)2 q a(3 \hat{j}-\hat{i})

  2. Option B:

    2qa(3i^−7j^)2 q a(3 \hat{i}-7 \hat{j})

  3. Option C:

    2qa(7i^−3j^)2 q a(7 \hat{i}-3 \hat{j})

    Correct
  4. Option D:

    2qa(3j^−7i^)2 q a(3 \hat{j}-7 \hat{i})

Answer: C

Step-by-step solution

p⃗=q1r⃗1+q2r⃗2+q3r⃗3p⃗=(2q)(−3a)j^+(3q)(2a)i^+(−4q)(−2a)i^p⃗=2qa(7i^−3j^)\begin{aligned} & \vec{p}=q_{1} \vec{r}_{1}+q_{2} \vec{r}_{2}+q_{3} \vec{r}_{3} & \vec{p}=(2 q)(-3 a) \hat{j}+(3 q)(2 a) \hat{i}+(-4 q)(-2 a) \hat{i} & \vec{p}=2 q a(7 \hat{i}-3 \hat{j}) \end{aligned}
Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
24 January, Morning Shift
Subject
Physics
Chapter
Electrostatics
Topic
Electric Dipole

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