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Physics · Electromagnetic Induction

JEE Main 2026 — 24 January, Morning Shift — Question 24

Match the List-I with List-II

List-IList-II
A. Magnetic inductionI. MLT−2 A−2\mathrm{M} \mathrm{L} \mathrm{T}^{-2} \mathrm{~A}^{-2}
B. Magnetic fluxII. ML2 T−2 A−2\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-2}
C. Magnetic permeabilityIII. ML0 T−2 A−1\mathrm{M} \mathrm{L}^{0} \mathrm{~T}^{-2} \mathrm{~A}^{-1}
D. Self inductanceIV. ML2 T−2 A−1\mathrm{M} \mathrm{L}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}

Choose the correct answer from the options given below:

  1. Option A:

    A−IV,B−III,C−I,D−IIA-IV,B-III,C-I,D-II

  2. Option B:

    A−III,B−IV,C−II,D−IA-III,B-IV,C-II,D-I

  3. Option C:

    A−I,B−III,C−IV,D−IIA-I,B-III,C-IV,D-II

  4. Option D:

    A−III,B−IV,C−I,D−IIA-III,B-IV,C-I,D-II

    Correct

Answer: D

Step-by-step solution

Magnetic induction F=qvB\mathrm{F}=\mathrm{qvB} [B]=[FqV][\mathrm{B}]=\left[\frac{\mathrm{F}}{\mathrm{qV}}\right] [B]=[MT−2 A−1][\mathrm{B}]=\left[\mathrm{MT}^{-2} \mathrm{~A}^{-1}\right] Magnetic Flux ( ϕ\phi ) ϕ=(B)\phi=(\mathrm{B}). (Area) [ϕ]=[ML2 T−2 A−1][\phi]=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] Magnetic Permeability [μ]=[MLT−2 A−2][\mu]=\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-2}\right] Self inductance Using U=12LI2\mathrm{U}=\frac{1}{2} \mathrm{LI}^{2} [Self inductance] =[ML2 T−2 A−1]=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] A - III, B - IV, C - I, D - II

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
24 January, Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction
Topic
Magnetic Flux, Faraday's Law and Lenz's Law

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