Physics · Current Electricity

JEE Main 2024 — 6 April, Shift 1 — Question 39

The value of unknown resistance ( $x$ ) for which the potential difference between B and D will be zero in the arrangement shown, is :

Option A:
$3 \Omega$
Option B:
$9 \Omega$
Option C:
$6 \Omega$
Correct
Option D:
$42 \Omega$

Answer: C

Step-by-step solution

In case of balanced Wheatstone Bridge $\frac{\mathrm{V}_{\mathrm{AB}}}{\mathrm{V}_{\mathrm{AD}}}=\frac{\mathrm{V}_{\mathrm{BC}}}{\mathrm{V}_{\mathrm{CD}}} \Rightarrow \frac{12}{6+\mathrm{x}}=\frac{0.5}{0.5}$

$\mathrm{x}=6 \Omega$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 6 April, Shift 1
Subject: Physics
Chapter: Current Electricity
Topic: Circuit Analysis, Kirchhoff's Law and Nodal Analysis

A wire of resistance R and radius r is stretched till its radius became r / 2 . If new resistance of the stretched wire is x R , then value…

Answer: C

Step-by-step solution

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