The specific heat at constant pressure of a real gas obeying PV 2 = RT equation is :

Physics · Thermodynamics

JEE Main 2024 — 6 April, Shift 1 — Question 40

The specific heat at constant pressure of a real gas obeying $\mathrm{PV}^{2}=\mathrm{RT}$ equation is :

$d Q=d u+d W$ $\mathrm{CdT}=\mathrm{C}_{\mathrm{V}} \mathrm{dT}+\mathrm{PdV}$

$\therefore \quad \mathrm{PV}^{2}=\mathrm{RT}$

$\mathrm{P}=$ constant $\mathrm{P}(2 \mathrm{VdV})=\mathrm{RdT}$

$\operatorname{PdV}=\frac{\mathrm{RdT}}{2 \mathrm{~V}}$

Put in equation (1)

\mathrm{C}=\mathrm{C}_{\mathrm{V}}+\frac{\mathrm{R}}{2 \mathrm{~V}}

Answer key and solution verified before publishing.

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