Chemistry · Structure of Atom

JEE Main 2026 — 4 April, Evening Shift — Question 51

The species having identical radii according to the Bohr's theory are : A. H (first orbit) B. He+\mathrm{He}^{+}(first orbit) C. He+\mathrm{He}^{+}(second orbit) D. Li2+\mathrm{Li}^{2+} (first orbit) E. Be3+\mathrm{Be}^{3+} (Second orbit) Choose the correct answer from the options given below:

  1. Option A:

    A and C Only

  2. Option B:

    A and E Only

    Correct
  3. Option C:

    B and E Only

  4. Option D:

    C and D Only

Answer: B

Step-by-step solution

A) → same (B) → same (C) → same (D) →r=90×23=903\rightarrow \mathrm{r}=\frac{90 \times^{2}}{3}=\frac{90}{3} (E) → same

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Structure of Atom
Topic
Bohr's Model of Atom
The species having identical radii according to the Bohr's theory are… | JEE Main 2026 PYQ with Solution · DhiX AI