Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2026 — 4 April, Evening Shift — Question 50

The correct order of total number of atoms of present in

(A) 2 moles of cyclohexane

(B) 684 g of sucrose

Option A:
$\mathrm{C}>\mathrm{A}>\mathrm{B}$
Option B:
$\mathrm{C}>\mathrm{B}>\mathrm{A}$
Option C:
B $>$ C $>$ A
Option D:
$\mathrm{B}>\mathrm{A}>\mathrm{C}$
Correct

Answer: D

Step-by-step solution

For (A): 2 moles of cyclohexane $\ce{C6H12}$ . Each molecule has 18 atoms. Total moles of atoms = $2 \times 18 = 36$ For (B): 684 g of sucrose $\ce{C12H22O11}$ . Molar mass = 342 g/mol. Moles of sucrose = $\frac{684}{342} = 2$ . Each molecule has 45 atoms. Total moles of atoms = $2 \times 45 = 90$ . For (C): 90.8 L of $\ce{H2}$ at STP (22.7 L/mol). Moles of $\ce{H2}$ = $\frac{90.8}{22.7} = 4$ . Each molecule has 2 atoms. Total moles of atoms = $4 \times 2 = 8$ . Order: (B) > (A) > (C).

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 4 April, Evening Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Introduction to Mole Concept