Chemistry · Ionic Equilibrium
JEE Main 2026 — 4 April, Evening Shift — Question 52
20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X) ? value of acetic acid is 4.75).
- Option A:
7
- Option B:Correct
4.45
- Option C:
3.5
- Option D:
4.82
Answer: B
Step-by-step solution
In experiment 1, 28.4 ml of NaOH is required for complete neutralisation, therefore for 14.2 ml , half equivalence point will be achieved to form acidic buffer.
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2026
- Subject
- Chemistry
- Chapter
- Ionic Equilibrium
- Topic
- pH of solution containing implicit reaction