Mathematics · Statistics

JEE Main 2026 — 5 April, Morning Shift — Question 31

The mean deviation about the mean for the data

xix_i579101215
fif_i862226

is equal to:

  1. Option A:

    40/13

  2. Option B:

    42/13

  3. Option C:

    44/13

    Correct
  4. Option D:

    46/13

Answer: C

Step-by-step solution

M.D. =∑fi∣xi−xˉ∣∑fi=\frac{\sum f_{i}\left|x_{i}-\bar{x}\right|}{\sum f_{i}} xˉ=∑fixi∑fi=40+42+18+20+24+9026\bar{x}=\frac{\sum f_{i} x_{i}}{\sum f_{i}}=\frac{40+42+18+20+24+90}{26} =23426=9=\frac{234}{26}=9 M.D. =8(4)+6(2)+2(0)+2(1)+2(3)+6(6)26=\frac{8(4)+6(2)+2(0)+2(1)+2(3)+6(6)}{26} =8426=4413=\frac{84}{26}=\frac{44}{13}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Statistics
Topic
Measures of Central Tendency
The mean deviation about the mean for the data x i 5 7 9 10 12 15 … | JEE Main 2026 PYQ with Solution · DhiX AI