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Mathematics · Probability

JEE Main 2026 — 5 April, Morning Shift — Question 30

A letter is known to have arrived by post either from KANPUR or from ANANTPUR. On the envelope just two consecutive letters AN are visible. The probability that the letter came from ANANTPUR is:

  1. Option A:

    46302

  2. Option B:

    10/17

    Correct
  3. Option C:

    12/19

  4. Option D:

    7/19

Answer: B

Step-by-step solution

P(I):12P(A/I)→15\mathrm{P}(\mathrm{I}): \frac{1}{2} \mathrm{P}(\mathrm{A} / \mathrm{I}) \rightarrow \frac{1}{5} P(II):12P(A/II)→27\mathrm{P}(\mathrm{II}): \frac{1}{2} \mathrm{P}(\mathrm{A} / \mathrm{II}) \rightarrow \frac{2}{7} ∴ Reqd. Prob =12×2712×15+12×27=27×5177=1017=\frac{\frac{1}{2} \times \frac{2}{7}}{\frac{1}{2} \times \frac{1}{5}+\frac{1}{2} \times \frac{2}{7}}=\frac{\frac{2}{7} \times 5}{\frac{17}{7}}=\frac{10}{17}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
5 April, Morning Shift
Subject
Mathematics
Chapter
Probability
Topic
Conditional Probability and Multiplication Theorem

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