Chemistry · d and f Block Elements

JEE Main 2024 — 9 April, Shift 1 — Question 70

The electronic configuration of Cu (II) is 3 d93 \mathrm{~d}^{9} whereas that of Cu(I)\mathrm{Cu}(\mathrm{I}) is 3 d103 \mathrm{~d}^{10}. Which of the following is correct?

  1. Option A:

    Cu(II)\mathrm{Cu}(\mathrm{II}) is less stable

  2. Option B:

    Stability of Cu(I)\mathrm{Cu}(\mathrm{I}) and Cu (II) depends on nature of copper salts

  3. Option C:

    Cu(II)\mathrm{Cu}(\mathrm{II}) is more stable

    Correct
  4. Option D:

    Cu(I)\mathrm{Cu}(\mathrm{I}) and Cu(II)\mathrm{Cu}(\mathrm{II}) are equally stable

Answer: C

Step-by-step solution

Cu(II)\mathrm{Cu}(\mathrm{II}) is more stable than Cu(I)\mathrm{Cu}(\mathrm{I}) because hydration energy of Cu+2\mathrm{Cu}^{+2} ion compensate IE2\mathrm{IE}_{2} of Cu .

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Introduction and Properties of Transition Elements
The electronic configuration of Cu (II) is 3 d 9 whereas that of Cu (… | JEE Main 2024 PYQ with Solution · DhiX AI