Chemistry · d and f Block Elements

JEE Main 2025 — 8 April, Evening Shift — Question 7

The correct decreasing order of spin only magnetic moment values (BM) of $\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}, \mathrm{Cr}^{2+}$ and $\mathrm{Cr}^{3+}$ ions is

Option A:
$\mathrm{Cu}^{+}>\mathrm{Cu}^{2+}>\mathrm{Cr}^{3+}>\mathrm{Cr}^{2+}$
Option B:
$\mathrm{Cu}^{2+}>\mathrm{Cu}^{+}>\mathrm{Cr}^{2+}>\mathrm{Cr}^{3+}$
Option C:
$\mathrm{Cr}^{3+}>\mathrm{Cr}^{2+}>\mathrm{Cu}^{+}>\mathrm{Cu}^{2+}$
Option D:
$\mathrm{Cr}^{2+}>\mathrm{Cr}^{3+}>\mathrm{Cu}^{2+}>\mathrm{Cu}^{+}$
Correct

Answer: D

Step-by-step solution

So order :

$\mathrm{Cr}^{2+}>\mathrm{Cr}^{3+}>\mathrm{Cu}^{2+}>\mathrm{Cu}^{+}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 8 April, Evening Shift
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Properties of compounds of 3d Series elements + Comparison between 3d, 4d, 5d