Statement I : The correct order of electronegativity of fluorine, oxygen nitrogen is F O N . Statement II : The oxidation state of oxygen in OF 2 is +2 and in Na 2 O is -2 . In the light of the above statements, choose the correct answer from the options given below

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2026 — 5 April, Morning Shift — Question 56

Statement I : The correct order of electronegativity of fluorine, oxygen nitrogen is $\mathrm{F}>\mathrm{O}>\mathrm{N}$ .

Statement II : The oxidation state of oxygen in $\mathrm{OF}_{2}$ is +2 and in $\mathrm{Na}_{2} \mathrm{O}$ is -2 .

In the light of the above statements, choose the correct answer from the options given below

\text{Statement-I}

\begin{aligned} (\text{EN})_{\text{F}} &= 4.0 \\ (\text{EN})_{\text{O}} &= 3.5 \\ (\text{EN})_{\text{N}} &= 3.0 \end{aligned} \qquad \text{on Pauling scale}$$

(\text{EN}){\text{F}} > (\text{EN}){\text{O}} > (\text{EN})_{\text{N}}

\text{Statement-II}

Oxidation state of oxygen in ${OF}_{2}$

\text{OF}_{2} \Rightarrow x - 1 \times 2 = 0

x = +2

Oxidation state of oxygen in ${Na}_{2}\text{O}$

\text{Na}_{2}\text{O} \Rightarrow +1 \times 2 + x = 0

x = -2

Both the statement I and statement II are correct.

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Exam: JEE Main 2026
Paper: 5 April, Morning Shift
Subject: Chemistry
Chapter: Periodicity of Elements and Periodic Properties
Topic: Periodicity in Chemical Properties (Ionization Energy, Electron Affinity, Electronegativity)