Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 2 April, Morning Shift — Question 12

On complete combustion 1.0 g of an organic compound ( X ) gave 1.46 g of CO2\mathrm{CO}_{2} and 0.567 g of H2O\mathrm{H}_{2} \mathrm{O}. The

empirical formula mass of compound ( X ) is _____\_\_\_\_\_ g. (Given molar mass in gmol−1C:12,H:1,O:16\mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16 )

  1. Option A:

    30

    Correct
  2. Option B:

    60

  3. Option C:

    15

  4. Option D:

    45

Answer: A

Step-by-step solution

%\% by mass of C=39.8\mathrm{C}=39.8

% \% by mass of H=6.3\mathrm{H}=6.3

%\% by mass of O=53.9\mathrm{O}=53.9

Emperical formula =CH2O=\mathrm{CH}_{2} \mathrm{O}

Emperical formula mass of (X)=30 g(\mathrm{X})=30 \mathrm{~g}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Percentage composition & Empirical Formula
On complete combustion 1.0 g of an organic compound ( X ) gave 1.46 g… | JEE Main 2025 PYQ with Solution · DhiX AI