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Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 2 April, Morning Shift — Question 18

0.1 mol of the following given antiviral compound (P)(P) will weigh _____\_\_\_\_\_ ×10−1 g\times 10^{-1} \mathrm{~g} (Given : molar mass in gmol−1H:1,C:12, N\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N} : 14, O:16, F: 19, I: 127

Question figure

Answer: 372

Numerical answer — enter this value.

Step-by-step solution

Formula of compound (P)

=C9O5FIN2H10=\mathrm{C}_{9} \mathrm{O}_{5} \mathrm{FIN}_{2} \mathrm{H}_{10}

Molar mass of ( P )

=372gmmole=372 \frac{\mathrm{gm}}{\mathrm{mole}}

0.1 mole mass =37.2 g=37.2 \mathrm{~g}

=372×10−1 g=372 \times 10^{-1} \mathrm{~g}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
2 April, Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Introduction to Mole Concept

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