Number of complexes with even number of electrons in t 2 g orbitals is - [ Fe ( H 2 O ) 6 ] 2+ , [ Co ( H 2 O ) 6 ] 2+ , [ Co ( H 2 O ) 6 ] 3+ , [ Cu ( H 2 O ) 6 ] 2+ , [ Cr ( H 2 O ) 6 ] 2+

Chemistry · Coordination Compounds

JEE Main 2024 — 8 April, Shift 1 — Question 72

Number of complexes with even number of electrons in $\mathrm{t}_{2 \mathrm{~g}}$ orbitals is -

$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ , $\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$

Option A:
1
Option B:
3
Option C:
2
Correct
Option D:
5

Answer: C

Step-by-step solution

${{\left[ \text{Fe}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}$

Electron in ${{\text{t}}_{2\text{ }\!\!~\!\!\text{ g}}}=4($ even $)$

Electron in ${{\text{t}}_{2\text{ }\!\!~\!\!\text{ g}}}=5$ (odd) ${{\left[ \text{Co}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{3+}}$

Electron in ${{\text{t}}_{2\text{ }\!\!~\!\!\text{ g}}}=6$ (even) ${{\left[ \text{Cu}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}$

Electron in ${{\text{t}}_{2\text{ }\!\!~\!\!\text{ g}}}=6$ (even) ${{\left[ \text{Cr}{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{2+}}$

Electron in ${{\text{t}}_{2\text{ }\!\!~\!\!\text{ g}}}=3$ (odd)

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 8 April, Shift 1
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Properties and importance of Coordination Complexes

An octahedral complex with the formula CoCl 3 nNH 3 upon reaction with excess of AgNO 3 solution given 2 moles of AgCl . Consider the…

Answer: C

Step-by-step solution

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