Match List I with List II List-I (Compound) List-II (Colour) --- --- --- --- A F e 4 [ Fe ( CN ) 6 ] 3 × x H 2 O I. Violet B. [ Fe ( CN ) 5 NOS ] 4- II. Blood Red C. [ Fe ( SCN )] 2+ III. Prussian Blue D. ( N H 4 ) 3 P O 4 × 12 Mo O 3 IV. Yellow Choose the correct answer from the options given below :

Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Main 2024 — 8 April, Shift 1 — Question 71

Match List I with List II

List-I (Compound)	List-II (Colour)
A	$\text{F}{{\text{e}}_{4}}{{\left[ \text{Fe}{{(\text{CN})}_{6}} \right]}_{3}}\cdot \text{x}{{\text{H}}_{2}}\text{O}$	I.	Violet
B.	${{\left[ \text{Fe}{{(\text{CN})}_{5}}\text{NOS} \right]}^{4-}}$	II.	Blood Red
C.	${{[\text{Fe}\left( \text{SCN} \right)]}^{2+}}$	III.	Prussian Blue
D.	${{\left( \text{N}{{\text{H}}_{4}} \right)}_{3}}\text{P}{{\text{O}}_{4}}\cdot 12\text{Mo}{{\text{O}}_{3}}$	IV.	Yellow

Choose the correct answer from the options given below :

$\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3} \cdot \mathrm{xH}_{2} \mathrm{O} \rightarrow$ Prussian Blue

$\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]^{4-} \rightarrow$ Violet

$[\mathrm{Fe}(\mathrm{SCN})]^{2+} \rightarrow$ Blood Red $\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} .12 \mathrm{MoO}_{3} \rightarrow$ Yellow

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