Mathematics · Limits, Continuity and Differentiability
JEE Main 2024 — 5 April, Shift 2 — Question 1
Let be given by , where denotes the greatest integer less than or
equal to . The number of points, where is not continuous, is :
- Option A:
6
- Option B:
3
- Option C:Correct
4
- Option D:
5
Answer: C
Step-by-step solution
Doubtful points :
at :
\left. \begin{array}{*{35}{r}}\text{RHL}\Rightarrow & f\left( \text{x} \right)=\left( 2-1-\left( -1 \right) \right)+0=2 \\{} & \text{f}\left( -1 \right)=2-1-\left( -1 \right)+1=3 \\\end{array} \right\}\text{ }\!\!~\!\!\text{ Dis}\text{. }\!\!~\!\!\text{ }
at :
\left. \begin{array}{*{35}{r}}\text{LHL}\Rightarrow & \text{f}\left( \text{x} \right)=8+2-1+3=12 \\{} & \text{f}\left( 2 \right)=8+2-2+4=12 \\\end{array} \right\}\text{ }\!\!~\!\!\text{ Cont}\text{. }\!\!~\!\!\text{ }
at :
\left. \begin{array}{*{35}{r}}\text{ }\!\!~\!\!\text{ LHL }\!\!~\!\!\text{ }\Rightarrow & 0+0-\left( -1 \right)+0=1 \\{} & \text{f}\left( 0 \right)=0 \\\end{array} \right\}\text{ }\!\!~\!\!\text{ Dis}\text{. }\!\!~\!\!\text{ }
at
\left. \begin{array}{*{35}{r}}\text{LHL}\Rightarrow & 2+1-0+0=3 \\{} & \text{f}\left( 1 \right)=3-1+1=3 \\\text{RHL}\Rightarrow & 2+1-1+1=3 \\\end{array} \right\}\text{ }\!\!~\!\!\text{ Cont}\text{. }\!\!~\!\!\text{ }
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 5 April, Shift 2
- Subject
- Mathematics
- Chapter
- Limits, Continuity and Differentiability
- Topic
- Continuity