Physics · Simple Harmonic Motion

JEE Main 2024 — 4 April, Shift 2 — Question 43

In simple harmonic motion, the total mechanical energy of given system is E. If mass of oscillating particle $P$ is doubled then

the new energy of the system for same amplitude is :

Answer: B

T.E. $=\frac{1}{2} \mathrm{kA}^{2}$

since A is same T.E. will be same

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