A 2 kg brick begins to slide over a surface which is inclined at an angle of 45 ° with respect to horizontal axis. The co-efficient of static friction between their surfaces is :

Physics · Friction

JEE Main 2024 — 4 April, Shift 2 — Question 42

A 2 kg brick begins to slide over a surface which is inclined at an angle of $45^{\circ}$ with respect to horizontal axis. The co-efficient of static friction between their surfaces is :

Option A:
1
Correct
Option B:
$\frac{1}{\sqrt{3}}$
Option C:
0.5
Option D:
1.7

Answer: A

Step-by-step solution

$m g \sin 45=f_{L}$

$\mathrm{mg} \cos 45=\mathrm{N}$

$\mathrm{f}_{\mathrm{L}}=\mu_{\mathrm{s}} \mathrm{N}$

$\mu_{\mathrm{s}}=\tan 45=1$

$\tan \theta=\mu_{\mathrm{s}}(\theta$ is angle of repose $)$

$\tan 45=\mu_{\mathrm{s}}=1$ correct option (1)

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 4 April, Shift 2
Subject: Physics
Chapter: Friction
Topic: Introduction to Frictional Force